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basename
(PHP 4, PHP 5, PHP 7, PHP 8)
basename — 返回路径中的文件名部分
说明
function basename(string $path, string $suffix = ""): string
给出一个包含有指向一个文件的全路径的字符串，本函数返回基本的文件名。
注意:
basename() 纯粹基于输入字符串操作，
它不会受实际文件系统和类似 ".." 的路径格式影响。
警告
basename() 是本地化的，所以如果要正确处理多字节字符的路径，需要用
setlocale() 正确设置匹配的 locale。如果 path
包含当前区域设置无效的字符，basename() 的行为未定义。
参数
path
一个路径。
在 Windows
中，斜线（/）和反斜线（\）都可以用作目录分隔符。在其它环境下是斜线（/）。
suffix
如果文件名是以
suffix 结束的，那这一部分也会被去掉。
返回值
返回指定 path 的基本名称。
示例
示例 #1 basename() 例子
echo "1) ".basename("/etc/sudoers.d", ".d").PHP_EOL;
echo "2) ".basename("/etc/sudoers.d").PHP_EOL;
echo "3) ".basename("/etc/passwd").PHP_EOL;
echo "4) ".basename("/etc/").PHP_EOL;
echo "5) ".basename(".").PHP_EOL;
echo "6) ".basename("/");
?>
以上示例会输出：
1) sudoers
2) sudoers.d
3) passwd
4) etc
5) .
6)
参见
dirname() - 返回路径中的目录部分
pathinfo() - 返回文件路径的信息
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用户贡献的备注 5 notes
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55
Anonymous ¶9 years ago
It's a shame, that for a 20 years of development we don't have mb_basename() yet!
// works both in windows and unix
function mb_basename($path) {
if (preg_match('@^.*[\\\\/]([^\\\\/]+)$@s', $path, $matches)) {
return $matches[1];
} else if (preg_match('@^([^\\\\/]+)$@s', $path, $matches)) {
return $matches[1];
}
return '';
}
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17
(remove) dot nasretdinov at (remove) dot gmail dot com ¶18 years ago
There is only one variant that works in my case for my Russian UTF-8 letters:
function mb_basename($file)
{
return end(explode('/',$file));
}
><
It is intented for UNIX servers
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9
swedish boy ¶16 years ago
Here is a quick way of fetching only the filename (without extension) regardless of what suffix the file has.
// your file
$file = 'image.jpg';
$info = pathinfo($file);
$file_name = basename($file,'.'.$info['extension']);
echo $file_name; // outputs 'image'
?>
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0
bobray at softville dot com ¶1 year ago
You might expect that echo basename('directory_name/') would return an empty string. Instead, it returns 'directory_name', without the slash.
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-1
KOmaSHOOTER at gmx dot de ¶21 years ago
If you want the current path where youre file is and not the full path then use this :)
echo('dir = '.basename (dirname($_SERVER['PHP_SELF']),"/"));
// retuns the name of current used directory
?>
Example:
www dir: domain.com/temp/2005/january/t1.php
echo('dirname
'.dirname($_SERVER['PHP_SELF']).'
');
// returns: /temp/2005/january
?>
echo('file = '.basename ($PHP_SELF,".php"));
// returns: t1
?>
if you combine these two you get this
echo('dir = '.basename (dirname($_SERVER['PHP_SELF']),"/"));
// returns: january
?>
And for the full path use this
echo(' PHP_SELF
'.$_SERVER['PHP_SELF'].'
');
// returns: /temp/2005/january/t1.php
?>
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